HOW TO ESTIMATE QUANTITY OF INGREDIENT IN MORTAR.

QUANTITY   OF   INGREDIENT   IN   MORTAR.....

Let start with ratio of mortar 1:6 and area for plaster is 200 m2  and thickness of plaster is 12 mm.

Area = 200 m2
Thickness =12 mm

we convert 12 mm in meter it is 12/1000 = 0.012 m

So wet volume of mortar = 200*0.012 = 2.4 m3
Total ingredient in mortar = 1+6  =7

Dry volume of mortar  = 2.4* 1.28 =3.072 m 3 ( we increase 28% volume in wet mortar because voids are present in cement and sand which may be reach 25 % to 28% and causing reduction in specified quantity Here we assume it 28%. )

Cement quantity = 1/7 *3.072 = 0.438 m3  
                        
                           = 0.438/0.0347 = 12.64 Bags (volume of 1 bag of cement = 0.0347)
                           = 12.64*50   =  632  kg          (weight of 1 cement bag =50 KG )


sand Quantity     =  6/7 *3.072 = 2.63 m3 

                           = 4471 kg  ( Assume density of sand 1700 kg/ m3 . Density = mass / volume)
 ( Than 1700= mass/ 2.63 = 1700*2.63 = 4471 kg)


water quantity let we assume water cement ratio is 0.45 

weight of water / weight of cement = w/C

0.45*632 = 285 kg


Cement = 632 kg
Sand     =  4471 kg
Water    =  285 kg