Acceptance criteria for strength of concrete.
1st) variation in percentage of stregth of single cube not more than and not less than 15% of average strength percentage of sample.
Let start with one example:
For M 35 grade of concrete the following results are arrives of a sample which is given below:
weight load strength
kg kn N/mm 2
8.720 - 1020.1 - 45.33
8.700 - 980.4 - 43.57
8.724 - 965.1 - 42.89
Average strength of sample: 43.93 N/mm2
If we convert individual strength in to percentage than we
N/mm 2 PERCENTAGE
45.33 - 129.51%
43.57 - 124.48% calculation for % (45.33/35)=129.51%
42.89 - 122.54%
And for average strength it will be come - 43.93- 125.51%
If we calculate variation of single strength percentage of cube to average strength percentage of sample than it will be following:
129.51 - 125.51 = 4%
124.48 - 125.51 = -1.03%
122.54 - 125.51 = -2.97%
So it is satisfy first criteria.
2nd) Strength of four non overlapping consecutive test result not less than
fck+3 or f ck +0.825* Standard deviation
( which ever greater)
and for individual it is f ck -3.
where f ck - characteristic of compressive strength of concrete.
if the sampling of concrete is not done by IS 456
Than it is
f ck+4 or f ck+ 0.825*standard deviation (which is more)
and for individual it is f ck-2
WHAT IS THE MEANING OF FOUR CONSECUTIVE NON OVERLAPPING TEST RESULT IS GIVEN BELOW:
LET START WITH EXAMPLE .
Here we describe it with M 35 grade of concrete strength, result of samples are given below:
wt. Load strength Average
Kg KN N/ mm2 N/mm2
8.510 980 43.55
8.512 921 40.93 41.81
8.628 922 40.97
8.610 898 39.11
8.598 878 39.02 39.22
8.602 890 39.55
8.600 1010 44.88
8.624 990 44.00 43.55
8.630 940 41.77
8.600 900.1 40.00
8.498 878.4 39.04 39.38
8.598 880.1 39.11
8.604 940.1 41.78
8.502 840.4 37.35 39.34
8.558 875.4 38.90
8.648 899.4 39.97
8.548 1000.1 44.44 42.21
8.595 950.4 42.24
For calculaing non overlapping consecutive test result: we must calculate results of strength of four consecutive samples which is non overlap i.e in above six samples results we add average strength of 1 2 3 4 sample for non overlapping consecutive result but we can't add 1 2 3 5 because in this case overlapping occure and non consecutive result.
If we need four consecutive test result for non overlapping cube from the above given example it must be
41.81+39.22+43.55+39.38 (average result of samples) = 40.99 N/mm 2
40.99 N/mm 2 is greater than f ck +3 i.e (35+3= 38 N/mm 2 ) than it is satisfy the 2nd criteria.
And for individual result it is come :35 N/mm 2 - 3 N/ mm 2 = 32 N/ mm 2 which is more than above any single result of sample.
HERE GRADE OF CONCRETE M 35...
1st) variation in percentage of stregth of single cube not more than and not less than 15% of average strength percentage of sample.
Let start with one example:
For M 35 grade of concrete the following results are arrives of a sample which is given below:
weight load strength
kg kn N/mm 2
8.720 - 1020.1 - 45.33
8.700 - 980.4 - 43.57
8.724 - 965.1 - 42.89
Average strength of sample: 43.93 N/mm2
If we convert individual strength in to percentage than we
N/mm 2 PERCENTAGE
45.33 - 129.51%
43.57 - 124.48% calculation for % (45.33/35)=129.51%
42.89 - 122.54%
And for average strength it will be come - 43.93- 125.51%
If we calculate variation of single strength percentage of cube to average strength percentage of sample than it will be following:
129.51 - 125.51 = 4%
124.48 - 125.51 = -1.03%
122.54 - 125.51 = -2.97%
So it is satisfy first criteria.
2nd) Strength of four non overlapping consecutive test result not less than
fck+3 or f ck +0.825* Standard deviation
( which ever greater)
and for individual it is f ck -3.
where f ck - characteristic of compressive strength of concrete.
if the sampling of concrete is not done by IS 456
Than it is
f ck+4 or f ck+ 0.825*standard deviation (which is more)
and for individual it is f ck-2
WHAT IS THE MEANING OF FOUR CONSECUTIVE NON OVERLAPPING TEST RESULT IS GIVEN BELOW:
LET START WITH EXAMPLE .
Here we describe it with M 35 grade of concrete strength, result of samples are given below:
wt. Load strength Average
Kg KN N/ mm2 N/mm2
8.510 980 43.55
8.512 921 40.93 41.81
8.628 922 40.97
8.610 898 39.11
8.598 878 39.02 39.22
8.602 890 39.55
8.600 1010 44.88
8.624 990 44.00 43.55
8.630 940 41.77
8.600 900.1 40.00
8.498 878.4 39.04 39.38
8.598 880.1 39.11
8.604 940.1 41.78
8.502 840.4 37.35 39.34
8.558 875.4 38.90
8.648 899.4 39.97
8.548 1000.1 44.44 42.21
8.595 950.4 42.24
For calculaing non overlapping consecutive test result: we must calculate results of strength of four consecutive samples which is non overlap i.e in above six samples results we add average strength of 1 2 3 4 sample for non overlapping consecutive result but we can't add 1 2 3 5 because in this case overlapping occure and non consecutive result.
If we need four consecutive test result for non overlapping cube from the above given example it must be
41.81+39.22+43.55+39.38 (average result of samples) = 40.99 N/mm 2
40.99 N/mm 2 is greater than f ck +3 i.e (35+3= 38 N/mm 2 ) than it is satisfy the 2nd criteria.
And for individual result it is come :35 N/mm 2 - 3 N/ mm 2 = 32 N/ mm 2 which is more than above any single result of sample.
HERE GRADE OF CONCRETE M 35...
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